Events A,B and C are exhaustive events. The odds against A are 8:3 and in favour of B are 2:5 . Find the odds in favour of C Share with your friends Share 0 Shruti Tyagi answered this Dear student, Given, three events A, B, and C are exhaustive. So,P(A)+P(B)+P(C)=1Now,Odds against A are 8:3 so, P(A)=38+3=311and,Odds against B are 5:2 so, P(B)=25+2=27put these values in above equation 311+27+P(C)=1⇒P(C)=3477⇒P(C)=1-P(C)=1-3477=4377Thus, odd in favour of C are P(C):P(C)=34:43 Regards -1 View Full Answer