# Experts answer it ASAP....

If V be the volume of liquid in the cylinder, at a height h of the water level then V=πr²h.

Differentiating both sides w.r.t time t,

we get $\frac{dV}{dt}$=πr²$\frac{dh}{dt}$

⇒Q=πr²$\frac{dh}{dt}$ or $\frac{dh}{dt}$=πr²Q

Note the $\frac{dV}{dt}$ represents the rate at which the volume of liquid in the cylinder increases, which is same as the rate of pouring of water through the tap.

Regards.

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