Experts pls help me to solve question no 12
12. If the side of a rhombus is 10 cm and one diagonal is 16 cm. then find the area of the rhombus.

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Let's take take triangle AOB of rhombus ABCD,
(with Pythagoras's theorem), a²+b²=c2
                                              8² (half of the diagonal of 16 cm) + b² = 10²
                                              b² = 100 - 64 = 36
                                    Therefore b = sqrt (36) = 6 cm
Therefore the second diagonal = 12 cm ( 6+6 cm)
area of a rhombus = 1/2 * diagonal 1 * diagonal 2
                                  1/2 * 16 * 12
             Therefore   :   1/2 * 8 * 12 = 96 cm²

Hope it helps