Experts plz help...we hv to factorise it

  • 0
Hello Yashvi!
To solve this answer, we need to know the cubic identities.
Question: Factorise x2-8/x
Now, we have to take 1/x as common. 
so now,
1/x(x3-8) (I have written x because when 1/x is multiplied with x3 x will get cancelled and the result will be x2)
If you notice inside the brackets, both x3 and 8 are cubes.
hence now applying the cubic identity a3-b3= (a-b)(a2+ab+b2
1/x(x3-23)
1/x(x-2)(x2+2(x)+22)
1/x(x-2)(x2+2x+4)

​​​​​​​regards

 
  • 2
What are you looking for?