# Explain:

Dear student,

A 6.90 M solution has 6.90 mol KOH in 1 L of solution.
Since , 1 L = 1000 cm3 , we can say that
6.90 mol KOH is present in 1000 cm3 solution
Mass of 6.90 mol KOH =
=

30% solution of KOH contains 30 g KOH in 100 g solution
1 g of KOH will be present in  solution
386.4 g of KOH will be present in solution = 1288 g solution
Density of solution = $\left(\frac{Mass}{Volume}\right)$ = $\left(\frac{1288}{1000}\right)$ = 1.288 g/cm-3
So, density of the solution = 1.288 g/cm-3

Regards

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