Factorise 6xy - 4y + 6 -9x by regrouping method. Please explain the regrouping of 6-9x to get the common factor 3x-2 as it is the same obtained in the 6xy -4y

The question should be;

$6xy-4y+6-9x\phantom{\rule{0ex}{0ex}}=6xy-9x-4y+6\phantom{\rule{0ex}{0ex}}=(6xy-9x)-(4y-6)\phantom{\rule{0ex}{0ex}}=3x(2y-3)-2(2y-3)\phantom{\rule{0ex}{0ex}}=(2y-3)(3x-2)$

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