factorise: (x-y)3+(y-z)3+(z-x)3

We know that,

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a3 + b3 + c3 =3abc if a+b+c = 0

(x-y) + (y-z) + (z-x) =0

So, (x-y)3 + (y-z)3 + (z-x)3 = 3(x-y)(y-z)(z-x)

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