Find answers to these answer. 
1) Find the (i) current flowing in the circuit & (ii) the potential difference  across 10 ohm resistor                                 

2) Find the current drawn from the battery by the network of four resistors shown in the figure.


 

Dear student,i) Rnet=20+10=30ohmCurrent =VRnet=330=0.1APotential difference across 10ohm =0.1×10=1Vii) R=10+10+10=30ohm1Rnet=130+110Rnet=7.5ohmcurrent=37.5=0.4ARegards

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