find d two third life(t2/3)of a first order reaction in which k=5.48*10 to d power -14 sec.......plsss tell me.....

Two-third life of a reaction means that, two-third of the reaction has completed in time t.

t can be calculated as:

at t = t2/3, the concentration of reactant left will be = [R]o-2/3[R]o = 1/3[R]o.

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