# find domain and range of (x2-9)/x-3

the given function is: $f\left(x\right)=\frac{{x}^{2}-9}{x-3}$
since the denominator can not be zero.
$x-3\ne 0\phantom{\rule{0ex}{0ex}}⇒x\ne 3$
the domain of the function is $R-\left\{3\right\}$

range of the function is $R-\left\{6\right\}$

hope this helps you

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