Find 'p' if the mean of the given data is 15.45.
Classes 0 – 6 6 – 12 12 – 18 18 – 24 24 –30
Frequency 6 8 p 9 7

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SUM OF FREQUENCY OR FI=30+P
SUM OF FIXI=468+15P
        MEAN=FIXI/FI
        15.45=468+15P/30+P
  
15.45(30+P)=468+15P
463.5+15.45P=468+15P
15.45P-15P=468-463.5
 0.45P=4.5
       P=4.5/0.45
       P=10
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  ​CI  ​  ​      fi       xi         fixi 0-6          6        3           18 6-12        8        9           72 12-18      p        15         15p  18-24      9        21         189 24-30      7        27         189 total-     30+p                468 + 15p     mean = 15.45 mean = sigma fixi / sigma fi or   15.45 = 468 + 15 p / 30 +p or    p = 10   Hence P= 10
 ​
 
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