Find the area of a trapezium whose parallel sides are 34cm, 20cm, and another sides are 13cm and 15cm.

ABCD is a trapezium.

AB = 34 cm, BC = 15 cm, CD = 20 cm and AD = 13 cm.

Draw CE || AD and CF ⊥ AB.

In quadrilateral AECD,

AE || CD and AD || CE

∴ Quadrilateral AECD is a parallelogram.

AE = CD = 20 cm (Opposite sides of parallelogram are equal)

and AD = CE = 13 cm (Opposite sides of parallelogram are equal)

BE = AB – AE = 34 cm – 20 cm = 14 cm

In ΔBCE,

CE = 13 cm, BE = 14 cm and BC = 15 cm.

Area of ΔBCE = 84 cm^{2}

Area of trapezium

Thus, the area of trapezium is 324 cm^{2}.

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