find the area of an isosceles triangle having unequal side as 12 cm and each of the equal sides as 24cm .also find its altitude corresponding to the unequal side

Dear student,


Here, Height(AD)= 24² - 6² = 540Now, Area of the ABC= 12*BC*AD = 12*12*540 = 139.427 cm²
Regards

  • 3
omg this wait thinking
  • -2
find it using herons formulae 
that is 
                the whole root of s(s-a)(s-b)(s-c)
                         where s= a+b+c/2
  • -2
wait
  • -1
Area = 36 root 15. Altitude = 6 root 15
  • 3
Root 15 is 3.87 in case u dont want to leave in root as area is never in roots
  • -2
here is a similar question :
1. A traffic signal board, indicating 'SCHOOL AHEAD', is an equilateral triangle with side 'a'. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board?

Answer

Length of the side of equilateral triangle = a
Perimeter of the signal board = 3a = 180 cm
∴ 3a = 180 cm ⇒ a = 60 cm
Semi perimeter of the signal board (s) = 3a/2
Using heron's formula,
Area of the signal board = √s (s-a) (s-b) (s-c)
                                       = √(3a/2) (3a/2 - a) (3a/2 - a) (3a/2 - a)
                                       = √3a/2 × a/2 × a/2 × a/2
                                       = √3a4/16
                                       = √3a2/4
                                       = √3/4 × 60 × 60 = 900√3 cm2
  • -1
Did my answer help you?
  • -1
Unequal sides = 12 cm
Equal sides = 24-12= 12 cm
​Each equal side = 12/2 = 6 cm
                 A triangle cannot be formed because,
1st side + 2nd side > 3rd side
                           But,             6+6=12              
Since you asked.
                    = sqrt of [12(12-12)(12-6)(12-6)]
                    = sqrt of [12*0*6*6]
                    = 0

Sorry the question is wrong,
                                                            But,  Hope it helps!! 
  • 2
What are you looking for?