Find the area of the quadrilateral whose vertices taken in order are (-4, -2), (-3, -5 ), (3, -2), and (2,3)........ Share with your friends Share 22 Lalit Mehra answered this Hi! Here is the answer to your question. Cheers! 89 View Full Answer Vartika answered this Let A (-4,-2) B(-3,-5) C(3,-2) and D (2,3)join BD. then, area tri. ABD + area tri. BCD = area quad. ABCD.so, area tri. ABD = 1/2 {-4(-5-3) -3(3+2) +2(-4+3)} = 1/2{ 32 -15 -2} = 1/2(15) = 15/2 ...(1)area tri. BCD = 1/2 {-3(-2-3) +3(3+5) +2(-5+2)} =1/2 { 15 +24 -6} = 1/2 (33) = 33/2 .....(2)adding (1) and (2) we get, area quad. ABCD = 15/2 + 33/2 = (15 + 33)/2 = 48/2 = 24..sq units...ans...:) -4 Guitars R0ck answered this my teacher said ans is 28......... also if we take diagonal AC then ans is coming as 13......... 0 Vartika answered this the answer wiil come the same, the only thing which you have to keep in mind is that take the coordinates as area tri.DAC and area tri. ABC....... 9 Arjun Siwach answered this let A =( -4 , -2 ) B = (-3 , -5 ) C = ( 3 , -2 ) D = ( 2 , 3 )now in triangle ABDarea = 1/2 { 2*(-2 + 5 ) - 4( -5 -3 ) -3( 3 + 2 ) } 1/2 { 2*3 - 4* (-8) - 3 * 5 ) 1/2{ 6 + 32 - 15} 23/2therefore area of triangle ABD = 23/2 unit square ------------1 now area of triangle BCDarea = 1/2{ -3( -2 -3 ) + 3( 3 + 5 ) + 2( -5 + 2 ) } 1/2 { -3*-5 + 3*8 + 2*(-3)} 1/2 { 15 + 24 - 6 } 33/2therefore area of triangle BCD = 33/2 unit square ------------- 2adding 1 & 223/2 + 33/2( 23 + 33 )/256 / 228therefore totall area = 28 unit square thumbs plzzzzzzzzzzzz 33 Arjun Siwach answered this hey vartika ur answer is wrong because in area of triangle ABD by mistake u have written 2(-4 + 3) correct point is 2( -2 + 5).......plzzzz check it........ 10 Arjun Siwach answered this thumbs up plzzzzzzzz 6 Vartika answered this o yeah...its by mistake... -4