find the area of the triangle whose sides are 42 cm, 34 cm, and 20 cm in length. hence, find the height  corresponding to the longest side??

 firstly use herons formula under root [s(s-a)(s-b)(s-c)]

s=42/2+34/2+20/2=48

now, root [ 48(48-42)(48-34)(48-20) ]

root [ 48(6)(14)(28) ]

root 112896

sry bt im unable to find after this

hope it helped u

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if u lyked it pls gave a thumbs up

cheers

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 i m too unable to find after this.....plz help me.........

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 make a trianlge ABC of 1 side=34cm one side=20 cm n the last side(base of the triangle) of 42cm
now use the heron's formula..according to the herons formula area of a triangle=under root [s(s-1st side of trianlge)(s-2nd side of triangle)(s-3rd side of trianle)].here s denotes the half of perimeter...perimeter is equals to the sum of all the sides of the triangle...that is 34+20+42 and it equals to 96..!!
 S is half of the perimeter........here our perimeter is 96.........so its half is 48...!!!
now just put your values in the formula
under root[48(48-34)(48-20)(48-42)]
under root[48*6*14*28]
under root(112896)
=336 cm.
it is given in the question to find the height corresponding to the largest side...here the largest side is 42cm....so it means that we have to take 42cm as our base......now area of triangle is also 1/2(half)*base of the triangle*height of the triangle
A=1/2*B*H
336=1/2*42*H
336=21*H
H=336/21
H=16cm..!!

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samaj aaya ya nahi...???

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tumahatra dimmag accha hai

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thanks

:)

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What is the height of the longest side
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Find the area of the triangle whose sides are 42 CM 34 cm and 20 CM in length hence find the height corresponding to the longest side
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See this and

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Find the area of the triangle whose sides are 42 CM 34 cm and 20 CM in length find the heck responding to the longest side
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