Find the coordinates of a point whose distance from (3,5) is 5 units and that from (0,1) is 10 units..

@Pdcool, check the statement again, as your statement is incomplete.

As the statement is : Find the coordinates (x,y) of a point whose distance from points (3,5) is 5 units & that from (0,1) is 10 units , given that 3x=2y

Solution:

Distance of (x,y) from the point (3,5) is 5 units.

and distance of (x,y) from the point (0,1) is 10 units.

subtracting equation (i) from (ii):

since 3x=2y put this in (iii)

∴ the desired point is (6,9).

  • 25

 now let the co-ordinate of that point (x,y)

then from distance formula we hav=under root(x1-x2)^2 + (y1-y2)^2==5 units

under root(3-x)^2 + (5 - y)^2=5

(3-x)^2 + (5 -y)^2=25 <square rooting both side)-----------(i)

nd similarly we have second equation as......

under root<sq.>(x1 - x2)^2 + (y1 - y2)^2=10 units

under root (0 - x)^2 + (1 - y)^2 =10

(0 -x)^2 + ( 1 -y)^2=100 (sq. rooting both sides)---------------(ii)

now solving this two equation we will get the corect answer ....i.e. the value of x and the value of y...........so the coordinates will be (x,y)

hope dis will help you!!!!

  • -21
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