find the derivative of cotx by the first principle? Share with your friends Share 19 Deepali Gupta answered this let f(x) = cot xd f(x) dx = limh→0f(x+h)-f(x)h =limh→0cot (x+h)-cot xh =limh→01hcos(x+h)sin(x+h)- cos(x)sin(x) =limh→01hsin(x)cos(x+h)-sin(x+h)cos(x)sin(x+h)sin(x) =limh→01hsin(x - x - h)sin(x+h)sin(x) =limh→01hsin(- h)sin(x+h)sin(x) =limh→0-sin(h)hlimh→01sin(x+h)sin(x) = (-1)1sin2 x = -cosec2 x .......Ans 105 View Full Answer
