Find the derivative of given function w r t corresponding independent variable y = x2 + x + 8 s - Physics - Physical World

Question

Find the derivative of given function w r t corresponding
independent variable
y = x2 + x + 8
s = 5t3 - 3t5
y = 5sin x
y = x2 + sin x

Manbar Singh · Accepted Answer

i y = x2 + x + 8Differentiating with respect to x, we get,dydx =
ddx x2 + ddx x + ddx 8⇒ dydx = 2x + 1 + 0 ddx xn = nxn-1ddx
constant = 0⇒ dydx = 2x + 1ii s = 5t2 - 3t5Differentiating
with respect to t, we getdsdt = 5 ddt t2 - 3 ddt t5⇒ dsdt = 5
2t - 3 5t4⇒ dsdt = 10t - 15t4

iii y = 5 sin xDifferentiating with respect to xdydx = 5 ddx sin
xdydx = 5 cos x as ddx sin x = cos xiv y = x2 + sin
xDifferentiating with respect to xdydx = ddx x2 + ddx sin x⇒
dydx = 2x + cos x

Find the derivative of given function w.r.t corresponding independent variable y = x2 + x + 8 s = 5t3 - 3t5 y = 5sin x y = x2 + sin x

Find the derivative of given function w.r.t corresponding independent variable

y = x² + x + 8

s = 5t³ - 3t5

y = 5sin x

y = x² + sin x