Find the discriminant of equation 2xsq-4x+3=0 and find the nature of its roots Share with your friends Share 0 Varun Rawat answered this The given equation is,2x2 + 4x + 3 = 0Comparing it with ax2 + bx + c = 0, we get a = 2; b = 4; c = 3Now, D = b2 - 4ac = 16 - 4×2×3 = 16-24 = -8 < 0Since, D < 0, the roots of the above equation are imaginary. 0 View Full Answer Swati Pandey answered this D=b^2-4ac=(-4)^2-4*2*3=16-24= -8 since D<0,therefore,the roots are imaginary 0 Makil Saiyad answered this Thanks for the answer 0
