Find the equation of the circle whose centre is (4,5) and touches the x axis .Find the coordinates of the points at which the circle cuts y axis.

Radius of the circle a=5 [since it touches x-axis(see fig.)]Equation of circle with center C(4,5) and radius 5(x-4)2+(y-5)2=25x2+y2-8x-10y+16=0Cricle cuts y-axis when x co-ordinate is zeroy2-10y+16=0(y-8)(y-2)=0y=8 or y=2Thus the cricle cuts y-axis at (0,8) and (0,2)

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Radius = 5
Hence equation
(x-4)^2 + (y-5)^2 = 25
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Coordinates are (0,8)&(0,2)
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