Find the equation of the circle with radius 5 whose centre lies on x-axis & passes through the point (2,3)?

GIVEN: r = 5

c(2,3)

centre lie on x-axis

i.e c(a,0)

A.T.Q

eq. (2-h)^{2} + (3-k)^{2} = 25 ----------------(1)

= (2-a)^{2} + y^{2} =25 -----------------------(2)

= 4 - 4a + a^{2} = 25

= a^{2} - 4a - 21 =0

= (a-6) (a + 2) =0

therefore a=6 or a= -2

hence

eq. a=6

x^{2} + y^{2} - 12x + 11= 0 ---------------ans

And a= -2

x^{2} + y^{2 }+ 4X -21 =0 -----------------ans