find the equation of the ellipse whose eccentricity is 3/4 ,focuson the y axis and passing through the point (6,4)

General equation of ellipse with focus on y -axis is
And e = $\sqrt{1-\frac{{b}^{2}}{{a}^{2}}}$
And the ellipse is passing through (6,4)
And b2 = a2 (1-e2 )
So putting the point ( 6,4) in general equation, we get 16/a+ 36/b2 = 1 (1)
So
And
So the equation of the ellipse will be y2 /(688/7) + x2 / (43) = 1

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