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Find the equation of the line through the intersection of lines 3x + 4y = 7 and x – y + 2 = 0 and

whose slope is 5.

First find point of intersection of 3x+4y=7 and x-y+2=0 by simultaneously solving these two equations 

we get , x= -1/7 y=13/7

Now we know that the line is passing thru this point and the slope is 5 

so by using one point form (y-y1) = m (x-x1)

(y-13/7) = 5 (x- (-1/7)

y- 13/7 = 5x +5/7

5x-y+5/7+13/7 =0

5x-y+18/7 =0........Answer

I hope u got it..

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View Full Answer

 wrong

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 Rahim answer provided by anmolbt is correct.You have to simplify it further then you will get the correct equation.

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Simplifying the equation : 5x - y + 18/7 = 0 , we would get the required answer ...

=> 5x - y + 18/7 = 0
Now , multiplying both sides by 7 ;
=> (5x)7 - (y)7 + (18/7)7 = (0)7
=> 35x - 7 y + 18 = 0 ....
This is the required answers that is given in the book..
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The next page

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hope it helps
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answer
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Rahim the answer written by anmol is absolutely correct. I think you have some mistake.
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The answer written by anmol is correct but we are supposed to do it by a different method using formula given in additional exercise right?
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