Find the equation of the line through the intersection of lines 3x + 4y = 7 and x – y + 2 = 0 and

whose slope is 5.

First find point of intersection of 3x+4y=7 and x-y+2=0 by simultaneously solving these two equations

we get , x= -1/7 y=13/7

Now we know that the line is passing thru this point and the slope is 5

so by using one point form (y-y1) = m (x-x1)

(y-13/7) = 5 (x- (-1/7)

y- 13/7 = 5x +5/7

5x-y+5/7+13/7 =0

5x-y+18/7 =0........Answer

I hope u got it..