FIND THE EQUIVALENT CAPACITANCE BETWEEN POINTS A AND B .

this is clear is the figure that the capacitance at juntion A are connected in series ,so equivalant capacitance will be  C*C/2C = C/2

now the new diagram consist only three capacitances ,the capacitace at middle is parallel to capacitance at B juction ,so equivalant capacitance will be  C+C = 2C

now the figure cnsist only two capacitance which are in series so  now  2C AND C/2 are in series so equivalant capacitance will be  2C/5

equivalant capacitance between the A and B is  2C/5.

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