Find the force required to stop a car of mass 100Kg with two passengers of
50 g each sitting inside,if it is moving at 60km/h speed and takes 5s to stop.

Dear Student

It is given that:

  • Mass of car = 100 kg
  • Two passengers with each of a mass of 50 g = 0.05 kg
  • Initial velocity = 60 km/h = 60 (5/18) = 50/3 m/s
  • Car takes 5 s to stop

Initial velocity u = 50/3 m/s
Final velocity  v = 0
v = u +ata =v-ut =0-50/35 =-103 m/s2Negative sign shows that this is deceleration.Total mass = mass of car+ mass of 2 passenger = 100 +2(0.050) =100 +0.1=100.1 KgForce = maHere a represents decelerationF =100.1×103 =10013 =333.67N

Regards

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