find the general solution for 2sinx +root3 cosx =1+ sinx Share with your friends Share 5 Vipin Verma answered this 2sinx + 3cosx = 1+ sinx Or sinx + 3cosx = 1 1-3cosx = sinx Squaring both sides ,we have1+3cos2x -23cosx = sin2x Or 1+3cos2x -23cosx = 1- cos2xOr 4cos2x -23cosx = 02cosx(2cosx -3) = 0Or cosx = 0 , so x = (2n+1)π2 , n = 0 ,1..And (2cosx -3) = 0Or cosx =32Or x = 2nπ ±π6 3 View Full Answer