find the general solution for 2sinx +root3 cosx =1+ sinx

2sinx + 3cosx = 1+ sinx
Or sinx + 3cosx = 1
1-3cosx = sinx Squaring both sides ,we have1+3cos2x -23cosx = sin2x Or 1+3cos2x -23cosx = 1- cos2xOr 4cos2x -23cosx = 02cosx(2cosx -3) = 0Or cosx = 0  , so x = (2n+1)π2 , n = 0 ,1..And (2cosx -3) = 0Or cosx =32Or x = 2nπ ±π6

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