find the HCF of 180,252 and 324 using euclid division lemma?

consider 252 and 324. here, a=324 and b=252

by euclid's division lemma-

a=bq+r, 0< or= r<b

324=252*1+72

252=72*3+36

72=36*2+0

therefore, HCF(252, 324)=36

Now consider 36 and 180. here a=180 and b=36.

by euclid's division lemma- a=bq+r, 0< or = r < b

180=36*5+0

therefore, HCF(180, 36)=36

Hence, HCF(180, 252, 324)=36