# find the HCF of 180,252 and 324 using euclid division lemma?

consider 252 and 324. here, a=324 and b=252

by euclid's division lemma-

a=bq+r, 0< or= r<b

324=252*1+72

252=72*3+36

72=36*2+0

therefore, HCF(252, 324)=36

Now consider 36 and 180. here a=180 and b=36.

by euclid's division lemma- a=bq+r, 0< or = r < b

180=36*5+0

therefore, HCF(180, 36)=36

Hence, HCF(180, 252, 324)=36

• 93
I dont know it... oops sorry man I really dnt know... :P :P
• -15
hcf of 322, 232,455

• -11
consider 252 and 324. here, a=324 and b=252 by euclid's division lemma- a=bq+r, 0
• -10
consider 252 and 324. here, a=324 and b=252 by euclid's division lemma- a=bq+r, 0
• -13
consider 252 and 324. here, a=324 and b=252 by euclid's division lemma- a=bq+r, 0
• -10
Using Euclid's division lemma find the HCF of 36575,3325and1330
• 1
Consider 252 and 324. here, a=324 and b=252 By euclid's division lemma- a=bq+r, 0
• 1
I don't know why this f*** Modi is doing this s**** and his b***is so s***

• -10
HCF of 180, 252 and 324:

324 = 1 x 180 + 144
180 = 1 x 144 + 36
144 = 4 x 36 + 0

So, HCF of 324 and 180 = 36

HCF of 252 and 36:
252 = 7 x 36 + 0
So, HCF of 252 and 36 is 36.

Hence, the HCF of 180, 252 and 324 is 36.
• 5
consider 252 and 324. here, a=324 and b=252 by euclid's division lemma- a=bq+r, 0
• 1
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