# Find the largest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively. Please answer fast because tommorow's exam!!!

first find the HCF of 2011 and 2623. Then add 9and5 to it respectively to it,and you will get your answer!!!!!

CHEER!!!!!!!!!

• -6

fine the greatest which divide 2011 and 2623, leaving remainders 9 and 5 respectively

• -11
2623 leaves remainder 5. 2623-5=2618. 2011 leaves remainder 9. 2011-9=2002 HCF of 2623 and 2011=2 so the largest that divides 2623 and 2011 is 12.
• 3
2011-9=2002
2623-5=2618
HCF = 2002, 2618

2002 = 2 x 7 x 143
2618 = 2 x 7 x 187
HCF = 2 x 7 =14

HCF = 2002, 2618 is 14
• -3
2011-9=2002
2623-5=2618
HCF = 2002, 2618

2002 = 2 x 7 x 143
2618 = 2 x 7 x 187
HCF?= 2 x 7 =14

HCF?= 2002, 2618 is 14
• 12
Find the greatest number which divides 2011 and 2623 leaving remainder 9 and 5 respectively. First step, 2011-9=2002 2623-5=2618 Second step, 2618=2002*1+616 2002=616*3+154 616=154*4+0 HCF=154
• 12
Let the number be x.

1.Subtract the remainders from the original numbers to get completely divisible numbers.
2011 - 9 = 2002
2623 - 5 = 2618
(Both of these are exactly divisible by x).

2. Find the HCF of 2002 and 2618.
2002 = 2 x 7 x 11 x 13
2618 = 2 x 7 x 11 x 17

HCF(2002, 2618) = 2 x 7 x 11 = 154

Therefore, x = 14
• -5
Sorry, I meant x = 154
• 6