Find the least number from which 26 is subtracted,the result is exactly divisible by 16, 24 and 36 Share with your friends Share 7 Manbar Singh answered this At first, we will find the LCM of 16, 24 and 36.The prime factorisation of 16,24 and 36 are :16 = 2×2×2×224 = 2×2×2×336 = 2×2×3×3LCM = 2×2×2×2×3×3 = 144Now, the required number = 144 + 26 = 170So, 170 is the smallest number from which when 26 is subtracted, then result becomes exactly divisible 16, 24 and 36. 5 View Full Answer