Find the least number from which 26 is subtracted,the result is exactly divisible by 16, 24 and 36

At first, we will find the LCM of 16, 24 and 36.The prime factorisation of 16,24 and 36 are :16 = 2×2×2×224 = 2×2×2×336 = 2×2×3×3LCM = 2×2×2×2×3×3 = 144Now, the required number = 144 + 26 = 170So, 170 is the smallest number from which when 26 is subtracted, then result becomes exactly divisible 16, 24 and 36.

  • 5
What are you looking for?