Find the least number which when divided by 100,120,150 always leaves a remainder 24.

The required number is 24 more than the LCM of 100, 120 and 150.

∴ LCM of 100, 120 and 150 = 2 × 2 × 3 × 5 × 5 × 2 = 600

Thus, the required number = 600 + 24 = 624

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