find the least sqare number which is exactly divisible by 6,9,15,and20

Least square number divisible by 6,9,15 and 20 = (L.C.M)2

L.C.M of 6,9,15 and 20 = 180

Least square number divisible by 6,9,15 and 20 = (180)2 = 32400

• 7

Ok

LCM Of 6,9,15 And 20 = 180

Prime Factorization Of 180 = 2*2*3*3*5

Only 5 Is Unpaired So WE Multiply 5 By LCM To Get A Perfect Square.

180*5 = 900

So Least Perfect Square- 900

• 10

first we have to take the LCM .

so LCM of 6 , 9 , 15 and 20 is 180

now after prime factorization of 180 we get 2 x 2 x 3 x 3 x 5

only 5 is left out . So we multiply 5 with 180 to get a perfect square

180 x 5 = 900

so , the least perfect square is 900

• 27
900
• -2
Lcm of 6,9,15,20=2*2*2*3*3*5=360 Then 5 and 2 is unpaired so we Multiply 360*5*2 = 3600
• -4
L.C.M of 6,9,15,20 is 540 and 540×5×3=8100
• -3

FIRST FIND THE LCM OF ALL NO.S TOGETHER = 540
540.3.5=8100
• -4
We will first find out the L.C.M of 6, 9 and 15.
L.C.M of 6, 9, 15 = 2 × 3 × 3 × 5 = 2 × 32 × 5 = 90
Since, we need to find the smallest square number divisible by 6, 9 and 15 and in above prime factorization of the numbers we observe that 2 and 5 does not appear in pair, therefore we multiply the L.C.M, 90 by 2 × 5.
Hence,
The required smallest square number = 90 × 2 × 5 = 900.
• 2
8100 ....
• -2
900
• 2
least square number is (180)square=32400
• -5
180 multiplied by 5 is 900
• 2
Give a too lenthy
• -2
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