Find the limiting and excess reagent in the following cases :- A. C( 50g)+ O2( 20g ) ------ > Co2 B. PCL3 ( 20g) + Cl2 (100g ) ----> PCL3 Share with your friends Share 0 Aditi Gupta answered this Solution: The reactions are as follows- A) C + O2 → CO2Moles of C = 5012 = 4.16 (Excess reagent)Moles of O2 = 2032 = 0.625Hence, the moles of oxygen is less, so here oxygen is the limiting reagent.B) PCl3 + Cl2 → PCl5Moles of PCl3 = 20137 = 0.145Moles of Cl2 = 10071=1.40 (Excess reagent)Hence, the limiting reagent is PCl3 since moles of PCl3 is less than chlorine. 0 View Full Answer