Find the measure of an angle, if seven times its complement is 10 less

than three times its supplement.

Let the angle to be determined be .

Sum of an angle and its complement is

Sum of an angle and its supplement is

Thus,

Complement of the angle is

Supplement of the angle is

It is given that:

Thus, the measure of the angle is

  • 28

Let the measure of the required angle be x degree

Then , measure of its complement=(90-x)degree

Measure of its supplement=(180-x)degree

7(90-x)=3(180-x)-10

630-7x=540-3x-10x

630-540= -13x+7x

90= -6x

x=90/-6

x=-90/6

x=-15

  • -8

 Let the measure of the required angle be x degree.

Then,measure of its complement=(90-x)degree

Measure of its supplement=(180-x)degree

7(90-x)= 3(180-x)-10

630-7x=540-3x-10

630-540-10=3x+7x

80=10x

x=80/10

x=8

Hence the measure of the required angle is 8 degree.

  • -6

its wrong@samriddhi 

it will be 630-540+10 and the final ans is 25o

u can verify it 

7 times 90-25 is 455

3{180-25}-10 is also 455 

  • 0
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