# Find the measure of an angle, if seven times its complement is 10 lessthan three times its supplement.

Let the angle to be determined be .

Sum of an angle and its complement is Sum of an angle and its supplement is Thus,

Complement of the angle is Supplement of the angle is It is given that: Thus, the measure of the angle is • 28

Let the measure of the required angle be x degree

Then , measure of its complement=(90-x)degree

Measure of its supplement=(180-x)degree

7(90-x)=3(180-x)-10

630-7x=540-3x-10x

630-540= -13x+7x

90= -6x

x=90/-6

x=-90/6

x=-15

• -8

Let the measure of the required angle be x degree.

Then,measure of its complement=(90-x)degree

Measure of its supplement=(180-x)degree

7(90-x)= 3(180-x)-10

630-7x=540-3x-10

630-540-10=3x+7x

80=10x

x=80/10

x=8

Hence the measure of the required angle is 8 degree.

• -6

its wrong@samriddhi

it will be 630-540+10 and the final ans is 25o

u can verify it

7 times 90-25 is 455

3{180-25}-10 is also 455

• 0
What are you looking for?