find the no. of complex numbers satisfying |z|=z+1+2i

Let, z=x+iy where x and y are real numbers.So,z=z+1+2ix2+y2=x+iy+1+2ix2+y2=x+1+iy+2On comparing the real and imaginary parts, we have,y+2=0y=-2And,x2+y2=x+1x2+4=x+1        put y=-2Squaring on both side,x2+4=x2+1+2x2x=3x=32Thusz=32-2i is the solution of given equation.

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