Find the nonzero value of k for which the roots of the quadratic equation 9x square - 3k x + K is equal to zero a real and equal

Dear Student!

The equation is… 9x^2 – 3kx +k =0
Since both roots are real and equal….D=0    ie. b^2-4ac=0
b=9k, a=9, c=k
9k^2- 4*9*k=0
K^2 – 4k= 0
K(k-4)=0
=> k=0 or k=4

Regards
 

  • 0
Hello Shreya dear, given equation is 9 x^2 - 3 k x + k = 0
The roots are equal implies discriminant b^2 - 4 a c = 0
==> b^2 = 4 a c
a = 9, b = (-3k) and c = k
Plugging 9 k^2 = 4 * 9 * k
==> k = 4
  • 0
What are you looking for?