find the number of atoms of each type present in 3.42grams of cane sugar ( C ₁₂ H₂₂O₁₁)

Molar mass of C₁₂H₂₂O₁₁ = 342 g/mol

1 mole of C₁₂H₂₂O₁₁ = 342 g

3.42 g of C₁₂H₂₂O₁₁ = 0.01 mole of C₁₂H₂₂O₁₁.

Mass of C in 342 g C₁₂H₂₂O₁₁ = 12 x 12 = 144 g

Mass of C in 3.42 g of C₁₂H₂₂O₁₁ = 1.44 g

Mass of H in 342 g C₁₂H₂₂O₁₁ = 22 x 1 = 22 g

Mass of H in 3.42 g of C₁₂H₂₂O₁₁ = 0.22 g

Mass of O in 342 g C₁₂H₂₂O₁₁ = 11 x 16 = 176 g

Mass of O in 3.42 g of C₁₂H₂₂O₁₁ = 1.76 g

Number of atoms = number of moles x 6.023 x 10²³ atoms

Number of C atoms=

Number of H atoms=

Number of O atoms=