find the number of square tiles each of side of 50cm which will be required to cover the floor of a room which is 4m long and 3m wide.

Area of each tile = ${\left(0.50\right)}^{2}{\mathrm{m}}^{2}=0.25{\mathrm{m}}^{2}$

Length of floor = 4 m

Width of floor = 3 m

So, Area of floor = $\left(4\times 3\right){\mathrm{m}}^{2}=12{\mathrm{m}}^{2}$

Therefore, Number of square tiles required = $\frac{\mathrm{Area}\mathrm{of}floor}{\mathrm{Area}\mathrm{of}\mathrm{each}\mathrm{square}tile}=\frac{12}{0.25}=48$

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