Find the perimeter of the rectangle whose length is 40cm and a dogonal is 41cm.
Let the diagonal be the hypotenuse of the rectangle. By Pythagoras theorem,
(Hypotenuse)2= (side one)2+ (side two)2
(41)2 = (40)2 + (side two)2
1681 = 1600 + (side two)2
(side two)2 = 1681-1600
(side two)2=81
(side two)=9
Perimeter of a rectangle = 2 (length + breadth)
=2 (40 +9)
=2*49
=98 cm
Therefore, perimeter of the rectangle is 98 cm.