Find the perimeter of the rectangle whose length is 40cm and a dogonal is 41cm.

Let the diagonal be the hypotenuse of the rectangle. By Pythagoras theorem,

(Hypotenuse)2= (side one)2+ (side two)2

(41)2 = (40)2 + (side two)2

1681 = 1600 + (side two)2

(side two)2 = 1681-1600

(side two)2=81

(side two)=9

Perimeter of a rectangle = 2 (length + breadth)

=2 (40 +9)

=2*49

=98 cm

Therefore, perimeter of the rectangle is 98 cm.

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=98 cm

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=98 cm

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Please find this answer

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160cm2
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Let the diagonal be the hypotenuse of the rectangle. By Pythagoras theorem,

(Hypotenuse)2= (side one)2+ (side two)2

(41)2 = (40)2 + (side two)2

1681 = 1600 + (side two)2

(side two)2 = 1681-1600

(side two)2=81

(side two)=9

Perimeter of a rectangle = 2 (length + breadth)

=2 (40 +9)

=2*49

=98 cm

Therefore, perimeter of the rectangle is 98 cm.
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