Find the points on y axis whose perpendicular distances from the line 4x-3y-12=0 is 3.

Dear Student,
Please find below the solution to the asked query:

As point lies on Y-axis, hence let the co-ordinates of point be 0,a.Perpendicular distance between points x1,y1 and line ax+by+c=0 is given by:p=ax1+by1+ca2+b2Hence distance between 0,a  and 4x-3y-12=0 will be given by:p=4×0-3×a-1242+-32-3a-1216+9=3  Given that p=3-3a+1225=33a+125=33a+12=153a+12=±153a+12=15 or 3a+12=-153a=15-12 or 3a=-15-123a=3 or 3a=-27a=1 or a=-9Hence co-ordinates of point will be 0,1 or 0,-9.

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Regards

  • 2
(0,1)
  • -6
What are you looking for?