Find the pressure exerted at the tip of a drawing pin if it is pushed against a board with a force of 20N. Assume the area of the tip to be 0.1mm2.

Pressure = Thrust/ Area  ( N/m2)
Thrust = 20 N
Area = 0.1 mm2 or 1 × 10 -1 mm2
Area = 1 × 10 -1 × 10-6 m2 (1 ×10-7 m2)
Thus, Pressure = 20 ×107    (1/a-n = an)
 
Pressure exerted by the pin is 2 ×108 Pa

  • 6
What are you looking for?