Find the second term after the middle term in the expansion of (x/2 + 2/x2)20 - Maths - Binomial Theorem

Question

Find the second term after the middle term in the expansion of (x/2
+ 2/x2)20

Ishwarmani · Accepted Answer

Dear Student, Please find below the solution to the asked query: Expression : x2 + 2x220∵ n = 20 is even,therefore 202+1th i
e
 11th term will be middle term∴2nd term after 11th term will be 13th termWe know that general term in the expansion of a+bn is given by :   tr+1 = Crn ar 
 bn-r⇒t13 = C1220x282x212         =16 × C1220x16 = 16×125970x16 = 2015520x16  Hope this information will clear your doubts about the topic
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Find the second term after the middle term in the expansion of (x/2 + 2/x2)20.

Find the second term after the middle term in the expansion of (x/2 + 2/x²)²⁰.