find the smallest square no. divisible by 8,15,20?

8 = 2 x 2 x 2

15 = 3 x 5

20 = 2 x 2 x 5

So, LCM = 2 x 2 x 2 x 3 x 5=120

As 3 and 5 are not in pair in LCM’s factor so we need to multiply 120 by 5 and three to make it a perfect square.

Required Number = 180 x 3 x 5 = 2700

  • -14
What are you looking for?