# find the value of k for which the points are colinear ( 3k-1, k-2) , ( k , k-7) and (k-1, -k-2)

Dear Student,

We have three points   ( 3 k - 1 , k - 2) , ( k , k - 7) and ( k - 1 , - k - 2)

We know if these points are collinear then the area of triangle from given points  is zero , Then given points are collinear  .

We know area of triangle from given three points  :

Area  =

Here x1 = 3k - 1 , x2 =  k , x3 = k - 1  and  y1 = k - 2 , y2 = k - 7 , y3 = - k - 2

So,