find the value of k for which the points are colinear ( 3k-1, k-2) , ( k , k-7) and (k-1, -k-2)
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Please find below the solution to the asked query:
We have three points ( 3 k - 1 , k - 2) , ( k , k - 7) and ( k - 1 , - k - 2)
We know if these points are collinear then the area of triangle from given points is zero , Then given points are collinear .
We know area of triangle from given three points :
Area =
Here x1 = 3k - 1 , x2 = k , x3 = k - 1 and y1 = k - 2 , y2 = k - 7 , y3 = - k - 2
So,
Hope this information will clear your doubts about topic.
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Please find below the solution to the asked query:
We have three points ( 3 k - 1 , k - 2) , ( k , k - 7) and ( k - 1 , - k - 2)
We know if these points are collinear then the area of triangle from given points is zero , Then given points are collinear .
We know area of triangle from given three points :
Area =
Here x1 = 3k - 1 , x2 = k , x3 = k - 1 and y1 = k - 2 , y2 = k - 7 , y3 = - k - 2
So,
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards