Find The value of M for which sum of zeros of the polynomial (m+1)x^2+(m-5)x+9 is equal to the half of - Maths - Coordinate Geometry

Question

Find The value of M for which sum of zeros of the polynomial
(m+1)x^2+(m-5)x+9 is equal to the half of product of zeroes

Abhishek Jha · Accepted Answer

Dear Student,
Here is the solution of your asked query:
The given polynomial is m+1x2+m-5x+9Comparing the given polynomial with standard form of quadratic equation ax2+bx+c; we havea=m+1, b=m-5 and c=9So, sum of zeroes=-ba=-m-5m+1And product of zeroes=ca=9m+1Now according to question we have;sum of zeroes=12 product of zeroes⇒-m-5m+1=129m+1⇒-m-5m+1=92m+1⇒-2m-5=9⇒-2m+10=9⇒-2m=9-10⇒2m=1⇒m=12Therefore the value of m is 12
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Find The value of M for which sum of zeros of the polynomial (m+1)x^2+(m-5)x+9 is equal to the half of product of zeroes