Hello,
For finding the value of sin 300 geometrically, we construct an equilateral triangle ABC of side 2 a. From A, we draw perpendicular AD to BC. Now, BD = CD = 1/2 BC = a
In triangle ABD, BAD + BDA + DAB = 180 (BY ANGLE SUM PROPERTY)
===> 600+ BAD + 90 0 = 180 0 (SINCE AD | BC AND ALL ANGLES ARE 60 0 in a equilateral triangle)
===> BAD = 30 0
IN RT TRIANGLE BAD,
SIN 30 0 = BD / AB= a / 2 a = 1/ 2
hence geometrically shown that sin 30 is 1/2
plz. answer my maths and chemistry question........