Dear Student, 34(3x-2) ×435 =342⇒34(3x-2) ×34-15 = 342⇒34(3x-2)×34(-1×5)=342⇒34{(3x-2)+(-5)}=342⇒34(3x-7)=342by compare power term as base of both are same 34(3x-7)=2⇒3x =2+7=9⇒x=93=3 Regards

Find the value of x....

Dear Student,

{(\frac{3}{4})}^{(3 x - 2)} \times {(\frac{4}{3})}^{5} = {(\frac{3}{4})}^{2} \Rightarrow {(\frac{3}{4})}^{(3 x - 2)} \times {\{{(\frac{3}{4})}^{- 1}\}}^{5} = {(\frac{3}{4})}^{2} \Rightarrow {(\frac{3}{4})}^{(3 x - 2)} \times {(\frac{3}{4})}^{(- 1 \times 5)} = {(\frac{3}{4})}^{2} \Rightarrow {(\frac{3}{4})}^{{(3 x - 2) + (- 5)}} = {(\frac{3}{4})}^{2} \Rightarrow {(\frac{3}{4})}^{(3 x - 7)} = {(\frac{3}{4})}^{2} b y c o m p a r e p o w e r t e r m a s b a s e o f b o t h a r e s a m e \frac{3}{4} (3 x - 7) = 2 \Rightarrow 3 x = 2 + 7 = 9 \Rightarrow x = \frac{9}{3} = 3

Regards

-1

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