Dear Student, 3 [2xx-5]2+10xx-5-24=0[2xx-5]2+10xx-5=24 4x2 + 10x (x - 5) = 24 (x - 5)2 [(a - b)2 = a2 + b2 - 2ab] 4x2 +10x2 - 50x = 24x2 + 600 – 240x 10x2 - 190x + 600 = 0 x2 - 19x + 60 = 0 x2 - 15x - 4x +60 = 0 (x - 15)(x - 4) = 0 Therefore, x = 15, x = 4 For remaining queries, we request you to post them in separate threads to have rapid assistance from our experts Regards!

Find the value of x.

Dear Student,

$3 . {[\frac{2 x}{x - 5}]}^{2} + \frac{10 x}{x - 5} - 24 = 0 {[\frac{2 x}{x - 5}]}^{2} + \frac{10 x}{x - 5} = 24$

4x²+ 10x (x - 5) = 24 (x - 5)²[(a - b)² = a² + b²- 2ab]

4x²+10x² - 50x = 24x²+ 600 – 240x

10x²- 190x + 600 = 0

x²- 19x + 60 = 0

x²- 15x - 4x +60 = 0

(x - 15)(x - 4) = 0

Therefore,

x = 15, x = 4

For remaining queries, we request you to post them in separate threads to have rapid assistance from our experts.

Regards!

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