find the volume of iron required to make an open box whose external dimensions are 36 cm*25cm*16.5cm,the box being 1.5cm throughout. if 1 cm3 of iron weighs 8.5 grams ,find the weight of the empty box in kilograms?

the external dimensions of the rectangular box =36cm*25cm*16.5cm

external volume of the box = 14850 cubic cm

since the thickness of the box is 1.5 cm and box is open.

internal length = (36-1.5*2)cm= 36-3=33 cm

internal breadth = 25-1.5*2=25-3=22 cm

internal height = 16.5-1.5 = 15 cm [since box is open]

therefore the internal dimensions of the rectangular box= 33cm*22cm*15cm

internal volume of the box = 10890 cubic cm

therefore the volume of the iron = external volume of the box - internal volume of the box

= 14850-10890

=3960 cubic cm

since 1 cubic cm of iron weighs 8.5 grams.

therefore weight of 3960 cubic cm = 3960*8.5=33660 gm

i.e. the weight of the empty box is 33.66 kg.

hope this helps you.

cheers!!