The answer is:first find the lcm of the denominator 2and 3 which is 6 now multiply it by 3 and 2 respectively with the numerator 1 .so now end up with 1/2 and1/3now you have to multiply it by 10 to get more than two numbers between them now you get 20/60 and 30/60 . And the numbers are 21/60,22/60,23/60......

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There are three methods and equivalent rational numbers method is the easiest one. What we have to do is, let the no. of rational nos. to be found be x (here three) and we have to multiply the numerator and the denominator with n+1 at first with 1/3 then 1/2. Now take any three rational numbers between the two resultant rational number

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1/3 and 1/2

can we write it as 1/2and 1/3

So here's the correct answer

= 1/2?4/4 and 1/3?4/4

= 4/8 and 4/12

Here we have to find 3 rational number b/w 1/3 & 1/2 so we will multiply 1/2 & 1/3 by 4 because 3+1=4

= 4/8 and 4/12

There are only three rational number

( 4/9 , 4/10 , 4/11 )

Hope it helps u....

can we write it as 1/2and 1/3

So here's the correct answer

= 1/2?4/4 and 1/3?4/4

= 4/8 and 4/12

Here we have to find 3 rational number b/w 1/3 & 1/2 so we will multiply 1/2 & 1/3 by 4 because 3+1=4

= 4/8 and 4/12

There are only three rational number

( 4/9 , 4/10 , 4/11 )

Hope it helps u....

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To represent???on the number line, we have to follow the steps given below:

(i) Draw a line and mark a point A on it. Mark point B such that AB = 3.5 unit and BC = 1 unit.

(ii) Find the mid-point of AC and mark it as M. Taking M as the center and MA as the radius, draw a semi-circle.

(iii) From B, draw a perpendicular to AC; Let it meet the semi-circle at D. Taking B as the center and BD as the radius, draw an are that intersects the line at E.

?

(i) Draw a line and mark a point A on it. Mark point B such that AB = 3.5 unit and BC = 1 unit.

(ii) Find the mid-point of AC and mark it as M. Taking M as the center and MA as the radius, draw a semi-circle.

(iii) From B, draw a perpendicular to AC; Let it meet the semi-circle at D. Taking B as the center and BD as the radius, draw an are that intersects the line at E.

?

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