Find value of cos (theta)

Dear student,from the figureIn triangle ABCABC=90°cosθ=BCAC=35sinθ=ABAC=45DCE+90°+ACB=180°       (angles on same straight line)+90°+θ=180° +θ=180° -90°+θ=90°=90°-θcos=cos90°-θ=sinθ=45cos=45Regards

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